Homework Assignment for 3.3-4
numbers = [0,1,2,3,4,5,6,7,8,9,10]
evens = []
for i in numbers:
if (numbers[i] % 2 == 0):
evens.append(numbers[i])
print(evens)
i = 1
starString = "*"
while i <= 5:
j = 1
while j <= i:
print ("*", end= "")
j += 1
print ()
i += 1
3.3 Video 2 Hacks
Practice Problems
- given the following code segment below:
a ⟵ 7
b ⟵ 1
c ⟵ 3
d ⟵ 4
a ⟵ b
b ⟵ c + d
d ⟵ b
find the value for a, b, c, d A = 1 since it becomes B B = 7 since its 4+3 C = 3 since its unchanges
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a = 1, b = 7, c = 3, d = 7- consider the following code segment:
hot ⟵ true
cold ⟵ false
cold ⟵ hot
hot ⟵ cold
what are the values of hot and cold after executing the code segment? 1. the value of hot is true, the value of cold is true
- the value of hot is false, the value of cold is true
- the value of hot is true, the value of cold is false
the value of hot is false, the value of cold is false
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</p>1. the value of hot is true, the value of cold is true
</details> THIS Iis becuase if you follow it hot = cold which = true and cold = hot which equals true
</li>Make TWO of your own code segments that contain at least 5 defined variables, then provide the answer and EXPLAIN why your answer is correct.
a ⟵ 1
b ⟵ 2
c ⟵ 3
d ⟵ 4
a ⟵ b
what is the value of A?
1. 2
- 5
- 8
a ⟵ 4
b ⟵ 3
c ⟵ 2
d ⟵ 1
d ⟵ c
What is the value of C
- 2
- 4 3. 1
- Sequencing
num1 = 3 num2 = 1 num3 = 5 num1 = num2 + num3 num2 = num1 + num3 # num2 is now the new num1 + num3 # number 1 is 6 as you add 5 + 1 making it 6. # number 2 is 11 becuase its added up within the numbers num 1 = 6 num 2 = 11
What is the value of num1 and num2?
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num1 = 6, num2 = 11
-
Test 1
firstName <- "Bob" lastName <- "Smith" var <- substring(firstName, 1, 1) name <- concat(lastName, var) email <- concat(name, "@gmail.com") DISPLAY(email)
-
What would the result be?
Hint: var = "B" name = "SmithB"
Answer SmithB@gmail.com Explanation: This is becuase the and the name is smithb and the email is the name with gmail.com
-
Test 2
word1 <- "computer" word2 <- "textbooks" length1 <- len(word1)/2 length2 <- len(word2)/3 first <- substring(word1, 2, len1) second <- substring(word2, len2+3, len2) newWord <- concat(first, second) DISPLAY(newWord) <mark